(20x^2+3x-9)=0

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Solution for (20x^2+3x-9)=0 equation:


Simplifying
(20x2 + 3x + -9) = 0

Reorder the terms:
(-9 + 3x + 20x2) = 0

Remove parenthesis around (-9 + 3x + 20x2)
-9 + 3x + 20x2 = 0

Solving
-9 + 3x + 20x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-3 + -4x)(3 + -5x) = 0

Subproblem 1

Set the factor '(-3 + -4x)' equal to zero and attempt to solve: Simplifying -3 + -4x = 0 Solving -3 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -4x = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -4x = 0 + 3 -4x = 0 + 3 Combine like terms: 0 + 3 = 3 -4x = 3 Divide each side by '-4'. x = -0.75 Simplifying x = -0.75

Subproblem 2

Set the factor '(3 + -5x)' equal to zero and attempt to solve: Simplifying 3 + -5x = 0 Solving 3 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -5x = 0 + -3 -5x = 0 + -3 Combine like terms: 0 + -3 = -3 -5x = -3 Divide each side by '-5'. x = 0.6 Simplifying x = 0.6

Solution

x = {-0.75, 0.6}

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